Find the angle between the two straight lines, r =3 i -2 j +4 k + (-2 i + j +2 k ) and r…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
Find the angle between the two straight lines, \(\overrightarrow{\mathrm{r}}=3 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+4 \hat{\mathrm{k}}+\lambda(-2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+2 \hat{\mathrm{k}})\) and
\(\vec{r}=\hat{i}+3 \hat{j}-2 \hat{k}+\mu(3 \hat{i}-2 \hat{j}+6 \hat{k})\):
\(\vec{r}=\hat{i}+3 \hat{j}-2 \hat{k}+\mu(3 \hat{i}-2 \hat{j}+6 \hat{k})\):
- \(\cos ^{-1}(4 / 21)\)
- \(\sin ^{-1}(4 / 21)\)
- \(\sin ^{-1}(17 / 21)\)
- \(\cos ^{-1}(17 / 21)\)
Answer
(A) ^ -1 (4 / 21)
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