The equation of the plane containing the two lines x-1 2 = y+1 -1 = z-0 3 and x -2 = y-2…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The equation of the plane containing the two lines
\(\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z-0}{3} \text { and } \frac{x}{-2}=\frac{y-2}{11}=\frac{z+1}{-1}\) is
\(\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z-0}{3} \text { and } \frac{x}{-2}=\frac{y-2}{11}=\frac{z+1}{-1}\) is
- 8x + y – 5z – 7 = 0
- 8x + y + 5z – 7 = 0
- 8x – y – 5z – 7 = 0
- none of these
Answer
(A) 8x + y – 5z – 7 = 0
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