The distance between the parallel planes a x+b y+c z+d=0 and a x+b y+c z+d^ =0 is :
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The distance between the parallel planes \(a x+b y+c z+d=0\) and \(a x+b y+c z+d^{\prime}=0\) is :
- \(\frac{\left|d+d^{\prime}\right|}{\sqrt{a^{2}+b^{2}+c^{2}}}\)
- \(\frac{\left|d-d^{\prime}\right|}{\sqrt{a^{2}+b^{2}+c^{2}}}\)
- \(\frac{d}{\sqrt{a^{2}+b^{2}+c^{2}}}\)
- none of these
Answer
(B) |d-d^ | a^ 2 +b^ 2 +c^ 2
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