A symmetrical form of the line of intersection of the planes x = ay + b and z = cy + d is:

Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry

1. \(\frac{\mathrm{x}-\mathrm{b}}{\mathrm{a}}=\frac{\mathrm{y}-1}{1}=\frac{\mathrm{z}-\mathrm{d}}{\mathrm{c}}\)
2. \(\frac{\mathrm{x}-\mathrm{b}-\mathrm{a}}{\mathrm{a}}=\frac{\mathrm{y}-1}{1}=\frac{\mathrm{z}-\mathrm{d}-\mathrm{c}}{\mathrm{c}}\)
3. 
4. \(\frac{\mathrm{x}-\mathrm{b}-\mathrm{a}}{\mathrm{~b}}=\frac{\mathrm{y}-1}{0}=\frac{\mathrm{z}-\mathrm{d}-\mathrm{c}}{\mathrm{~d}}\)

Answer

(B) x - b - a a = y -1 1 = z - d - c c

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