Vectors a ~b make an angle = 2 3 . If | a |=1,| ~b |=2 then ( a +3 b ) (3 a - b )^ 2 =
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
Vectors \(\overrightarrow{\mathrm{a}} \& \overrightarrow{\mathrm{~b}}\) make an angle \(\theta=\frac{2 \pi}{3}\). If \(|\overrightarrow{\mathrm{a}}|=1,|\overrightarrow{\mathrm{~b}}|=2\) then \((\vec{a}+3 \vec{b}) \times(3 \vec{a}-\vec{b})^{2}=\)
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Answer
(D) 300
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