Let a = j - k and c = i - j - k . Then the vector b satisfying a b + c =0 and a b =3, is

Mathematics · JEE Main · NTA ExamsThree Dimensional Geometry

Let \(\vec{a}=\hat{\mathrm{j}}-\hat{\mathrm{k}} \text { and } \overrightarrow{\mathrm{c}}=\hat{\mathrm{i}}-\hat{\mathrm{j}}-\hat{\mathrm{k}}\). Then the vector \(\overrightarrow{\mathrm{b}}\) satisfying \(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}+\overrightarrow{\mathrm{c}}=0\) and \(\vec{a} \cdot \vec{b}=3,\) is
  1. \(-\hat{\mathrm{i}}+\hat{\mathrm{j}}-2 \hat{\mathrm{k}}\)
  2. \(2 \hat{\mathrm{i}}-\hat{\mathrm{j}}+2 \hat{\mathrm{k}}\)
  3. \(\hat{i}-\hat{j}-2 \hat{k}\)
  4. \(\hat{i}+\hat{j}-2 \hat{k}\)

Answer

(A) - i + j -2 k

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