Find the equation of the line which passes through (1,2,3) and is parallel to the line…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
Find the equation of the line which passes through \((1,2,3)\) and is parallel to the line whose equation is \(x=a y+b\), \(z=c y+d\).
- \(\frac{x-1}{a}=\frac{y-2}{1}=\frac{z-3}{c}\)
- \(\frac{x-b}{a}=\frac{y-c}{2}=\frac{z-d}{3}\)
- \(\frac{x-z}{a}=\frac{y-3}{c}=\frac{z-1}{d}\)
- None of these
Answer
(A) x-1 a = y-2 1 = z-3 c
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