Consider the shown arrangement. Assume all surfaces to be smooth. If N represents…

Physics · JEE Main · NTA Exams — Laws of Motion

Consider the shown arrangement. Assume all surfaces to be smooth. If N represents magnitudes of normal reaction between block and wedge, then acceleration of M along horizontal is equal to:

1. \(\frac{N \sin \theta}{M}\)along + ve x-axis
2. \(\frac{N \cos \theta}{M}\)along –ve x-axis
3. \(\frac{N \sin \theta}{M}\) along –ve x-axis
4. \(\frac{N \sin \theta}{m+M}\) along –ve x-axis

Answer

(C) N M along –ve x-axis

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