A rope of length L and mass M is hanging from a rigid support. The tension in the rope at…
Physics · JEE Main · NTA Exams — Laws of Motion
A rope of length L and mass M is hanging from a rigid support. The tension in the rope at a distance x from the rigid support is:
- Mg
- \(\left(\frac{L-x}{L}\right) M g\)
- \(\left(\frac{L}{L-x}\right) M g\)
- \(\frac{X}{L} M g\)
Answer
(B) ( L-x L ) M g
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Given below are two statements. STATEMENT - 1: The coefficient of friction must be greater than 1. STATEMENT…
- Three balls A, B and C (m_ A =m_ C =4 m_ B ) are placed on a smooth horizontal surface. Ball B collides with…
- A bullet weighing 50 gm leaves the gun with a velocity of 30 m/s. If the recoil speed imparted to the gun is…
- In the motion of a rocket, physical quantity which is conserved is
- A bag of mass M hangs by a long thread and a bullet of mass m comes horizontally with velocity v and gets…
- Two cars of unequal masses use similar tyres. If they are moving at the same initial speed, the minimum…
- Force is the product of mass and acceleration. This formula cannot be deduced from Newton' second law of…
- Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A…
More Laws of Motion questions · Browse all practice questions