A bag of mass M hangs by a long thread and a bullet of mass m comes horizontally with…

Physics · JEE Main · NTA ExamsLaws of Motion

A bag of mass M hangs by a long thread and a bullet of mass m comes horizontally with velocity v and gets caught in the bag. Then for the combined (bag + bullet) system,
  1. momentum\(=\frac{\mathrm{mvM}}{\mathrm{~m}+\mathrm{M}}\)
  2. KE = \(\frac{1}{2} m v^{2}\)
  3. KE = \(\frac{1}{2}(m+M) v^{2}\)
  4. KE = \(\frac{m^{2} v^{2}}{2(M+m)}\)

Answer

(D) KE = m^ 2 v^ 2 2(M+m)

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