A bag of mass M hangs by a long thread and a bullet of mass m comes horizontally with…
Physics · JEE Main · NTA Exams — Laws of Motion
A bag of mass M hangs by a long thread and a bullet of mass m comes horizontally with velocity v and gets caught in the bag. Then for the combined (bag + bullet) system,
- momentum\(=\frac{\mathrm{mvM}}{\mathrm{~m}+\mathrm{M}}\)
- KE = \(\frac{1}{2} m v^{2}\)
- KE = \(\frac{1}{2}(m+M) v^{2}\)
- KE = \(\frac{m^{2} v^{2}}{2(M+m)}\)
Answer
(D) KE = m^ 2 v^ 2 2(M+m)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Force is the product of mass and acceleration. This formula cannot be deduced from Newton' second law of…
- In the motion of a rocket, physical quantity which is conserved is
- Two blocks are in contact on a frictionless table. One has mass m and the other 2 m. A force F is applied on…
- A rope of length L and mass M is hanging from a rigid support. The tension in the rope at a distance x from…
- The coefficient of friction between the tyres and road is 0.4 . The minimum distance covered before attaining…
- A 2kg of block of wood rests on a long table top. A 5 g bullet moving horizontally with a speed of 150 m/s is…
- A block of mass 4 kg is placed on a rough horizontal plane. A time dependent force F = kt2 acts on the block…
- A machine gun fires a steady stream of bullets at the rate of n per minute into a stationary target in which…
More Laws of Motion questions · Browse all practice questions