The coefficient of friction between the tyres and road is 0.4 . The minimum distance…
Physics · JEE Main · NTA Exams — Laws of Motion
The coefficient of friction between the tyres and road is 0.4 . The minimum distance covered before attaining a speed of 8 m/s starting from rest is nearly: (g = 10 m/s2)
- 8.0 m
- 4.0 m
- 10.0 m
- 16.0 m
Answer
(A) 8.0 m
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A body of mass m strikes a stationary body of mass M and undergoes an elastic collision. After collision, m…
- In the above problem, if a push of 5 N is applied on the lighter mass, the force exerted by the lighter mass…
- Consider a system of two identical particles. One of the particles is at rest and the other has an…
- A mass M is suspended by a rope from a rigid support at A as shown. Another rope is tied at the end B and it…
- A rope of length L and mass M is hanging from a rigid support. The tension in the rope at a distance x from…
- A rocket of mass 100 kg burns 0.1 kg of fuel per sec. If velocity of exhaust gas is 1 km/s, then it lifts…
- A given object takes n times more time to slide down 45° rough inclined plane as it takes to slide down a…
- Given below are two statements. STATEMENT - 1: The coefficient of friction must be greater than 1. STATEMENT…
More Laws of Motion questions · Browse all practice questions