Two blocks are connected by a string as shown in the diagram. The upper block is hung by…
Physics · JEE Main · NTA Exams — Laws of Motion
Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force F applied on the upper string produces an acceleration of 2m/s2 in the upward direction in both the blocks. If T and T’ be the tensions in the two parts of the string, then
- \(T=70.8 \mathrm{~N}\)and \(T^{\prime}=472 \mathrm{~N}\)
- \(T=58.8 \mathrm{~N}\) and \(T^{\prime}=472 \mathrm{~N}\)
- \(T=70.8 \mathrm{~N}\)and \(T^{\prime}=58.8 \mathrm{~N}\)
- \(T=70.8 \mathrm{~N}\)and \(T^{\prime}=0\)
Answer
(A) T=70.8 ~N and T^ =472 ~N
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