Pushing force making an angle to the horizontal (towards bottom of the block) is applied…
Physics · JEE Main · NTA Exams — Laws of Motion
Pushing force making an angle \(\theta\) to the horizontal (towards bottom of the block) is applied on a block of weight W placed on a horizontal table. If the angle of friction is \(\phi\), the magnitude of force required to move the body is equal to:
- \(\frac{W \cos \theta}{\cos (\theta-\phi)}\)
- \(\frac{W \sin \phi}{\cos (\theta+\phi)}\)
- \(\frac{W \tan \phi}{\sin (\theta-\phi)}\)
- \(\frac{W \sin \phi}{\tan (\theta-\phi)}\)
Answer
(B) W ( + )
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