Two identical metal plates are given positive charges Q 1 and Q 2 ( 1 ) respectively. If…
Physics · JEE Advanced · NTA Exams — Electrostatics
Two identical metal plates are given positive charges Q1 and Q2 (< Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
- (Q1 + Q2)/2C
- (Q1 + Q2)/C
- (Q1 – Q2)/C
- (Q1 – Q2)/2C
Answer
(D) (Q 1 – Q 2 )/2C
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