A system of three parallel plates each of area A are separated by distance d 1 and d 2 …

Physics · JEE Advanced · NTA ExamsElectrostatics

A system of three parallel plates each of area A are separated by distance d1 and d2. The space between them is filled with dielectric of permittivities ε1 and ε2. The permitivity of free space is ε0. The equivalent capacitance of system is
  1. \(\frac{\varepsilon_{0} \varepsilon_{2} \mathrm{~d}}{\varepsilon_{1} \mathrm{~d}_{1}+\varepsilon_{2} \mathrm{~d}_{2}}\)
  2. \(\frac{\varepsilon_{0} \mathrm{~A}}{\varepsilon_{1} \mathrm{~d}_{1}+\varepsilon_{2} \mathrm{~d}_{2}}\)
  3. \(\frac{\varepsilon_{1} \varepsilon_{2} \varepsilon_{0} \mathrm{~d}}{\varepsilon_{1} \mathrm{~d}_{1}+\varepsilon_{2} \mathrm{~d}_{2}}\)
  4. \(\frac{\varepsilon_{1} \varepsilon_{2} \mathrm{~A}}{\varepsilon_{2} \mathrm{~d}_{1}+\varepsilon_{1} \mathrm{~d}_{2}}\)

Answer

(D) _ 1 _ 2 ~A _ 2 ~d _ 1 + _ 1 ~d _ 2

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