The expression for the capacity of the capacitor formed by compound dielectric placed…
Physics · JEE Advanced · NTA Exams — Electrostatics
The expression for the capacity of the capacitor formed by compound dielectric placed between the plates of a parallel plate capacitor as shown in figure, will be (area of plate = A)
- \[\frac{\varepsilon_{0} \mathrm{~A}}{\left(\frac{\mathrm{~d}_{1}}{\mathrm{~K}_{1}}+\frac{\mathrm{d}_{2}}{\mathrm{~K}_{2}}+\frac{\mathrm{d}_{3}}{\mathrm{~K}_{3}}\right)}\]
- \[\frac{\varepsilon_{0} \mathrm{~A}}{\left(\frac{\mathrm{~d}_{1}+\mathrm{d}_{2}+\mathrm{d}_{3}}{\mathrm{~K}_{1}+\mathrm{K}_{2}+\mathrm{K}_{3}}\right)}\]
- \(\frac{\varepsilon_{0} \mathrm{~A}\left(\mathrm{~K}_{1} \mathrm{~K}_{2} \mathrm{~K}_{3}\right)}{\mathrm{d}_{1} \mathrm{~d}_{2} \mathrm{~d}_{3}}\)
- \(\varepsilon_{0}\left(\frac{\mathrm{AK}_{1}}{\mathrm{~d}_{1}}+\frac{\mathrm{AK}_{2}}{\mathrm{~d}_{2}}+\frac{\mathrm{AK}_{3}}{\mathrm{~d}_{3}}\right)\)
Answer
(A) _ 0 ~A ( ~d _ 1 ~K _ 1 + d _ 2 ~K _ 2 + d _ 3 ~K _ 3 )
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Figure shows two concentric, conducting shells of radii r and 2r. The outer shell is given a charge Q. The…
- In a parallel–plate capacitor, the plates are kept vertical. The upper half of the space between the plates…
- In the circuit shown, initially there is no charge on capacitors and keys S 1 and S 2 are open. The values of…
- How should three charges q, 2and 8be arranged on a 9 cm long line such that the potential energy of the…
- In the figure shown, if the linear charge density is λ, then the net electric field at O will be
- A field line is shown in the figure. This field cannot represent.
- Two equal negative charges –are fixed at points (0, –a) and (0, a) on y-axis. A positive charge is released…
- The space between the plates of a parallel plate capacitor is filled completely with a dielectric substance…
More Electrostatics questions · Browse all practice questions