The eccentricity of the conic represented by x 2 – y 2 – 4x + 4y + 16 = 0 is
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The eccentricity of the conic represented by
x2 – y2 – 4x + 4y + 16 = 0 is
x2 – y2 – 4x + 4y + 16 = 0 is
- 1
- \(\sqrt{2}\)
- 2
- 1/2
Answer
(B) 2
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