The area of the closed figure bounded by the curves y= x , y= 4-3 x y=0 is
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
The area of the closed figure bounded by the curves \(y=\sqrt{x}, y=\sqrt{4-3 x} \& y=0\) is
- \(4 / 9\)
- \(8 / 9\)
- \(16 / 9\)
- none
Answer
(B) 8 / 9
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