The area of the closed figure bounded by the curves y= x ; y=1+ 2 x x= 2 is

Mathematics · JEE Advanced · NTA Exams — Integral Calculus

1. \(\frac{\pi+4}{4}\)
2. \(\frac{3 \pi}{4}\)
3. \(\frac{3 \pi+4}{4}\)
4. \(\frac{3 \pi-4}{4}\)

Answer

(D) 3 -4 4

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• Let f(x)= x (1+x^ n )^ 1 / n for n ≥ 2 and Then x^ n-2 g(x) d x equals
• If I = (2 x +3) dx ( x ^ 2 +2 x +3 ) x ^ 2 +2 x +4 , then I equals
• If f(x)= x x [0, 2 ], f(x)+f( -x)= 2 x ( 2 , ] and f(x)=f(2 -x) x ( , 2 ] , then the area enclosed by y=f(x)…
• If the line x = α divides the area of region R = ( x , y ) ∈ R 2 : x 3 ≤ y ≤ x , 0 ≤ x ≤ 1 into two equal…
• The ratio in which the curve y=x^ 2 divides the region bounded by the curve; y= ( x 2 ) & the x- axis as…
• If I = e ^ x ( x x+ x) d x then I equals :
• Consider the function f(x)= _ 0 ^ x [t] d t where x>0 and is the integral part of . Then
• Let a , b , c be non zero real numbers such that _ 0 ^ 1 (1+ ^ 8 x ) (a x^ 2 +b x+c ) d x= _ 0 ^ 2 (1+ ^ 8 x…

More Integral Calculus questions · Browse all practice questions