The ratio in which the curve y=x^ 2 divides the region bounded by the curve; y= ( x 2 ) &…
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
The ratio in which the curve \(y=x^{2}\) divides the region bounded by the curve; \(y=\sin \left(\frac{\pi x}{2}\right)\) & the \(x-\) axis as 
varies from \(0\) to \(1\), is
varies from \(0\) to \(1\), is- \(2: \pi\)
- \(1: 3\)
- \(3: \pi\)
- \((6-\pi): \pi\)
Answer
(D) (6- ):
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Assertion : If 1 f(x) d x=2 log | f (x)|+c, then f(x)= x 2 Reason : When f (x) = x 2 , then 1 f(x) d x= 2 x d…
- If I= ( 2 ) d then I equals
- The value of _ - ^ ^ 2 x 1+a^ x d x , a > 0 is
- For which of the following values of m , is the area of the region bounded by the curve y = x – x 2 and the…
- The area bounded by the curves y = f ( x ), the x -axis and the ordinates x = 1, x = b is ( b – 1) sin (3 b +…
- If I= _ k=1 ^ 98 _ k ^ k+1 k+1 x(x+1) d x , then
- Assertion : e^ ^ -1 x (1- x 1-x^ 2 ) d x=e^ ^ -1 x 1-x^ 2 +c Reason : e ^ g(x) (g^ ( x ) f( x )+f^ ( x ) ) dx…
- If _ 0 ^ x^ 2 (1+ x)^ 2 d x=A then _ 0 ^ 2 x^ 2 ^ 2 (x / 2) (1+ x)^ 2 d x=
More Integral Calculus questions · Browse all practice questions