If I= _ k=1 ^ 98 _ k ^ k+1 k+1 x(x+1) d x , then
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
\(\text { If } I=\sum_{k=1}^{98} \int_{k}^{k+1} \frac{k+1}{x(x+1)} d x \text {, then }\)
- I > loge 99
- I < loge 99
Answer
(C) I e 99
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