Evaluate (x+2) d x (x^ 2 +3 x+3 ) x+1
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
Evaluate \(\int \frac{(x+2) d x}{\left(x^{2}+3 x+3\right) \sqrt{x+1}}\)
- \(\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{\sqrt{3} \sqrt{x+1}}{-x}\right)+c\)
- \(\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{\sqrt{3} \sqrt{x+1}}{x}\right)+c\)
- \(\frac{1}{\sqrt{3}} \tan ^{-1}\left(\frac{\sqrt{3} \sqrt{x+1}}{-x}\right)+c\)
- \(\frac{1}{\sqrt{3}} \tan ^{-1}\left(\frac{\sqrt{3} \sqrt{x+1}}{x}\right)+c\)
Answer
(A) 2 3 ^ -1 ( 3 x+1 -x )+c
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