_ 0 ^ / 2 f( 2 x) x d x=k _ 0 ^ / 4 f( 2 x) x d x where equals
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
\(\int_{0}^{\pi / 2} f(\sin 2 x) \sin x d x=k \int_{0}^{\pi / 4} f(\cos 2 x) \cos x d x\) where
equals
equals- \(2\)
- \(4\)
- \(\sqrt{2}\)
- \(2 \sqrt{2}\)
Answer
(C) 2
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