_ 1 / e ^ x t 1+t^ 2 d t+ _ 1 / e ^ x dt t (1+t^ 2 ) =
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
\(\int_{1 / e}^{\tan x} \frac{\mathrm{t}}{1+t^{2}} d t+\int_{1 / e}^{\cot x} \frac{\mathrm{dt}}{t\left(1+t^{2}\right)}=\)
- \(2 \tan e\)
- \(1\)
- \(\tan e+\cot e\)
Answer
(C) 1
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The area of the plane figure bounded in first quadrant by y=x^ 1 / 3 ; y=-x^ 2 +2 x+3 ; y=2 x-1 and the axis…
- The value of the integral ^ 3 x+ ^ 5 x ^ 2 x+ ^ 4 x d x is
- If I= _ 0 ^ 1 e^ t t+1 d t then _ a-1 ^ a e^ -t t-a-1 d t=
- ( x 3 + 3 x 2 + 3 x + 3 + ( x + 1) cos ( x + 1)) dx is equal to
- If I_ m, n = _ 0 ^ 1 t^ m (1+t)^ n d t then the expression for I ( m, n ) in terms of I m + 1, n – 1 is
- Let f^ (x)= 192 x^ 3 2+ ^ 4 x for all x ∈ R with f ( 1 2 )=0 . If m _ 1 / 2 ^ 1 f(x) d x M then the possible…
- ( p x q x) d x is equal to (where p, q ∈ Z)
- The area bounded by y=2-|2-x| and y= 3 |x| is
More Integral Calculus questions · Browse all practice questions