If I= _ 0 ^ 1 e^ t t+1 d t then _ a-1 ^ a e^ -t t-a-1 d t=
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
If \(I=\int_{0}^{1} \frac{e^{t}}{t+1} d t\) then \(\int_{a-1}^{a} \frac{e^{-t}}{t-a-1} d t=\)
- \(\mathrm{Ie}^{\mathrm{a}}\)
- \((-\mathrm{I}) \mathrm{e}^{\mathrm{a}}\)
- \((-\mathrm{I}) \mathrm{e}^{-\mathrm{a}}\)
- \(\mathrm{Ie}^{-\mathrm{a}}\)
Answer
(C) (- I ) e ^ - a
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