If I_ 1 = _ -4 ^ -5 e^ (x+5)^ 2 d x and I_ 2 =3 _ 1 / 3 ^ 2 / 3 e^ 9[x-(2 / 3)]^ 2 d x…
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
If \(I_{1}=\int_{-4}^{-5} e^{(x+5)^{2}} d x\) and \(I_{2}=3 \int_{1 / 3}^{2 / 3} e^{9[x-(2 / 3)]^{2}} d x\) then the value of \(\mathrm{I}_{1}+\mathrm{I}_{2}\) is
- \(0\)
- \(1\)
- \(e^{-1}\)
- \(\bar{e}\)
Answer
(A) 0
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