The value of the definite integral _ 0 ^ 1 (1+e^ -x^ 2 ) d x is
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
The value of the definite integral \(\int_{0}^{1}\left(1+e^{-x^{2}}\right) d x\) is
- –1
- 2
- 1 + e–1
- none of these
Answer
(D) none of these
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