_ 0 ^ 1 / 3 d x (2 x^ 2 +1 ) x^ 2 +1 =
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
\[\int_{0}^{1 / \sqrt{3}} \frac{d x}{\left(2 x^{2}+1\right) \sqrt{x^{2}+1}}=\]
- \(\frac{\pi}{2}\)
- \(\tan ^{-1} 2\)
- \(\tan ^{-1} 1 / 2\)
- \(\pi\)
Answer
(C) ^ -1 1 / 2
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