If ( x 2 + x ) dx = x log |x | + ( x + 1) log | x +1| + k, then k equals
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
If \(\int \log\)(x2 + x) dx = x log |x| + (x + 1) log |x +1| +k, then k equals
- 2x + log |x + 1| + c
- 2x – log |x + 1| + c
- constant
- None
Answer
(D) None
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