Value of the parameter a such that the area bounded by y=a^ 2 x^ 2 +a x+1 , co-ordinate…
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
Value of the parameter a such that the area bounded by
\(y=a^{2} x^{2}+a x+1\), co-ordinate axes and the line \(x=1\), attains it’s least value, is equal to
\(y=a^{2} x^{2}+a x+1\), co-ordinate axes and the line \(x=1\), attains it’s least value, is equal to
- \(-\frac{1}{4}\)
- \(-\frac{1}{2}\)
- \(-\frac{3}{4}\)
- \(-1\)
Answer
(C) - 3 4
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