The sum of the series 1+3 x+6 x^ 2 +10 x^ 3 + is (where |x| < 1)

Mathematics · JEE Main · NTA ExamsProgression and Series

The sum of the series
\(1+3 x+6 x^{2}+10 x^{3}+\ldots \ldots \infty \text { is }\)(where |x| < 1)
  1. \(\frac{1}{(1-x)^{2}}\)
  2. \(\frac{1}{1-x}\)
  3. \(\frac{1}{(1+x)^{2}}\)
  4. \(\frac{1}{(1-x)^{3}}\)

Answer

(D) 1 (1-x)^ 3

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Progression and Series questions · Browse all practice questions