The sum of the series 1+3 x+6 x^ 2 +10 x^ 3 + is (where |x| < 1)
Mathematics · JEE Main · NTA Exams — Progression and Series
The sum of the series
\(1+3 x+6 x^{2}+10 x^{3}+\ldots \ldots \infty \text { is }\)(where |x| < 1)
\(1+3 x+6 x^{2}+10 x^{3}+\ldots \ldots \infty \text { is }\)(where |x| < 1)
- \(\frac{1}{(1-x)^{2}}\)
- \(\frac{1}{1-x}\)
- \(\frac{1}{(1+x)^{2}}\)
- \(\frac{1}{(1-x)^{3}}\)
Answer
(D) 1 (1-x)^ 3
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