Let the sum of the first n terms of a non-constant A.P., a 1 , a 2 , a 3 , ... be 50 n+…
Mathematics · JEE Main · NTA Exams — Progression and Series
Let the sum of the first n terms of a non-constant A.P., a1, a2, a3, ... be \(50 n+\frac{n(n-7)}{2} A\), where A is a constant. If d is the common difference of this A.P., then the ordered pair (d, a50) is equal to:
- (50, 50 + 46A)
- (50, 50 + 45A)
- (A, 50 + 45A)
- (A, 50 + 46A)
Answer
(D) (A, 50 + 46A)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If x= _ n=a ^ (-1)^ n ^ 2 n and y= _ n=a ^ ^ 2 n , for 0< < 4 , then :
- Let a_ 1 , a_ 2 , , a_ 1 be in AP and h_ 1 , h_ 2 , ., h_ 1 , be in HP. If a _ 1 = h _ 1 = Z and a_ 1! =h_ 1!…
- The sum of first n (odd) terms of an A.P. whose middle term is m is
- Let f(x) be a polynomial function of second degree. If f(1)=f(-1) and a, b, c are in AP, then f ' (a), f '…
- If the roots of the equation a(b-c) x^ 2 +b(c-a) x+c(a-b)=0 are equal, then a_ 1 b_ 1 c are in
- In a geometric progression consisting of positive terms, each term equals the sum of the next two terms…
- If a_ k a_ k-1 +a_ k-1 a_ k-2 =2 a_ k a_ k-2 , k 3 and here S_ p = _ k=1 ^ p 1 a_ k and given that S_ 2 p S_…
- If 19th term of a non-zero A.P. is zero, then its (49th term) : (29th term) is:
More Progression and Series questions · Browse all practice questions