In a geometric progression consisting of positive terms, each term equals the sum of the…

Mathematics · JEE Main · NTA ExamsProgression and Series

In a geometric progression consisting of positive terms, each term equals the sum of the next two terms. Then, the common ratio of this progression equals
  1. \(\frac{1}{2}(1-\sqrt{5})\)
  2. \(\frac{1}{2} \sqrt{5}\)
  3. \(\sqrt{5}\)
  4. \(\frac{1}{2}(\sqrt{5}-1)\)

Answer

(D) 1 2 ( 5 -1)

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