In a geometric progression consisting of positive terms, each term equals the sum of the…
Mathematics · JEE Main · NTA Exams — Progression and Series
In a geometric progression consisting of positive terms, each term equals the sum of the next two terms. Then, the common ratio of this progression equals
- \(\frac{1}{2}(1-\sqrt{5})\)
- \(\frac{1}{2} \sqrt{5}\)
- \(\sqrt{5}\)
- \(\frac{1}{2}(\sqrt{5}-1)\)
Answer
(D) 1 2 ( 5 -1)
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