If the sum of an infinite decreasing GP is 3 and the sum of squares of it's terms is 9/2…
Mathematics · JEE Main · NTA Exams — Progression and Series
If the sum of an infinite decreasing GP is 3 and the sum of squares of it's terms is 9/2, then the sum of cubes of it's terms is
- \(\frac{108}{13}\)
- \(\frac{105}{13}\)
- \(\frac{729}{8}\)
- None of these
Answer
(A) 108 13
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