Sum of the series 4 + 6 + 9 + 13 + 18 + ......... n terms, is

Mathematics · JEE Main · NTA Exams — Progression and Series

1. \(\frac{n}{6}\left(n^{2}+3 n+20\right)\)
2. n² + 3n + 20
3. \(\frac{n}{3}\left(n^{2}+3 n+20\right)\)
4. None of these

Answer

(A) n 6 (n^ 2 +3 n+20 )

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