The sum of n terms of the series 4 3 + 10 9 + 28 27 + is :
Mathematics · JEE Main · NTA Exams — Progression and Series
The sum of n terms of the series \(\frac{4}{3}+\frac{10}{9}+\frac{28}{27}+\ldots\) is :
- \(\frac{3^{n}(2 n+1)+1}{2\left(3^{n}\right)}\)
- \(\frac{3^{n}(2 n+1)-1}{2\left(3^{n}\right)}\)
- \(\frac{3^{n} n-1}{2\left[3^{n}\right]}\)
- \(\frac{3^{n}-1}{2}\)
Answer
(B) 3^ n (2 n+1)-1 2 (3^ n )
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