If t _ n = 1 4 ( n +2)( n +3) for n = 1, 2, 3, .........., then 1 t_ 1 + 1 t_ 2 + 1 t_ 3…
Mathematics · JEE Main · NTA Exams — Progression and Series
If \(\mathrm{t}_{\mathrm{n}}=\frac{1}{4}(\mathrm{n}+2)(\mathrm{n}+3)\)for n = 1, 2, 3, .........., then
\(\frac{1}{t_{1}}+\frac{1}{t_{2}}+\frac{1}{t_{3}}+\ldots \ldots+\frac{1}{t_{2003}}=\)
\(\frac{1}{t_{1}}+\frac{1}{t_{2}}+\frac{1}{t_{3}}+\ldots \ldots+\frac{1}{t_{2003}}=\)
- \(\frac{4006}{3006}\)
- \(\frac{4006}{3008}\)
- \(\frac{4006}{3009}\)
Answer
(D) 4006 3009
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