Let a_ 1 , a_ 2 , a_ 3 , ., a_ n be a GP such that a _ 4 a _ 6 = 1 4 and a_ 2 +a_ 5 =216…
Mathematics · JEE Main · NTA Exams — Progression and Series
Let \(a_{1}, a_{2}, a_{3}, \ldots \ldots \ldots ., a_{n}\) be a GP such that \(\frac{\mathrm{a}_{4}}{\mathrm{a}_{6}}=\frac{1}{4}\) and \(a_{2}+a_{5}=216 .\) Then integral value of a1 is
- \(12\)
- \(18\)
- \(24\)
- \(9\)
Answer
(A) 12
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