_ n=0 ^ ( _ e x )^ n n! is equal to
Mathematics · JEE Main · NTA Exams — Progression and Series
\(\sum_{n=0}^{\infty} \frac{\left(\log _{e} x\right)^{n}}{n!}\) is equal to
- \(\log _{R} x\)
- x
- \(\frac{1}{\log _{e} x}\)
- \(\frac{1}{x}\)
Answer
(B) x
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