The first and the n th terms of a GP are a and b respectively and if 'p' is the product…
Mathematics · JEE Main · NTA Exams — Progression and Series
The first and the nth terms of a GP are a and b respectively and if 'p' is the product of the first n-terms, then p2 equals
- \((a b)^{n}\)
- \((a b)^{n / 2}\)
- \((a b)^{n-1}\)
- None of these
Answer
(B) (a b)^ n / 2
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