Let T_ p be the general term of an A.P whose first term is - 1 2 and common difference is…
Mathematics · JEE Main · NTA Exams — Progression and Series
Let \(T_{p}\) be the general term of an A.P whose first term is \(-\frac{1}{2}\) and common difference is 1, then \(\sum_{r=1}^{n} \sqrt{1+T_{r} T_{r+1} T_{r+2} T_{r+3}}=\)
- \(\frac{n(n+1)(2 n+1)}{6}-\frac{5 n}{4}\)
- \(\frac{n(n+1)(2 n+1)}{6}-\frac{5 n}{4}+\frac{1}{4}\)
- \(\frac{n(n+1)(2 n+1)}{6}-\frac{5 n}{4}+\frac{1}{2}\)
- None of these
Answer
(C) n(n+1)(2 n+1) 6 - 5 n 4 + 1 2
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