The solution of the differential equation y dx + (x + x 2 y) dy = 0 is
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the differential equation
y dx + (x + x2y) dy = 0 is
y dx + (x + x2y) dy = 0 is
- \(-\frac{1}{x y}=c\)
- \(-\frac{1}{x y}+\log y=c\)
- \(\frac{1}{x y}+\log y=c\)
- log y = cx
Answer
(B) - 1 x y + y=c
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