If the sum of the squares of the roots of the equation x^ 2 -( x-2) x-(1+ x)=0 is least…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If the sum of the squares of the roots of the equation \(x^{2}-(\sin x-2) x-(1+\sin x)=0\) is least, then \(\text { II }\) is
- \(\pi / 4\)
- \(\pi / 3\)
- \(\pi / 2\)
- \(\pi / 6\)
Answer
(C) / 2
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