The value of k for which the equation 3x 2 + 2x (k 2 + 1) + k 2 – 3k + 2 = 0 has roots of…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
The value of k for which the equation
3x2 + 2x (k2 + 1) + k2 – 3k + 2 = 0
has roots of opposite signs, lies in the interval
3x2 + 2x (k2 + 1) + k2 – 3k + 2 = 0
has roots of opposite signs, lies in the interval
- (–∞, 0)
- (–∞, –1)
- (1, 2)
- (3/2, 2)
Answer
(C) (1, 2)
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