If z is a complex number such that |z| ≥ 2, then the minimum value of |z+ 1 2 | is K…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If z is a complex number such that
|z| ≥ 2, then the minimum value of \(\left|z+\frac{1}{2}\right|\) is K, then find 10K.
|z| ≥ 2, then the minimum value of \(\left|z+\frac{1}{2}\right|\) is K, then find 10K.
- \(10\)
- \(15\)
- \(20\)
- \(25\)
Answer
(B) 15
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