Let II , II 2 be the roots of x^ 2 +x+1=0 , then the equation whose roots are II 31 , II…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
Let \(\text { II }\), \(\text { II }\)2 be the roots of \(x^{2}+x+1=0\), then the equation whose roots are \(\text { II }\)31, \(\text { II }\)62 is
- \(\mathbf{x}^{2}-\mathbf{x}+1=0\)
- \(x^{2}+x-1=0\)
- \(\mathbf{x}^{2}+\mathbf{x}+1=0\)
- \(x^{60}+x^{30}+1=0\)
Answer
(A) x ^ 2 - x +1=0
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