The number of real roots of the equation (x-1)^ 2 +(x-2)^ 2 +(x-3)^ 2 =0 is
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
The number of real roots of the equation \((x-1)^{2}+(x-2)^{2}+(x-3)^{2}=0\) is
- \(0\)
- \(2\)
- \(4\)
- \(6\)
Answer
(A) 0
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