If x 2 - x + 1 = 0, then the value of _ n=1 ^ 5 (x^ n + 1 x^ n )^ 2 is
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If x2 - x + 1 = 0, then the value of \(\sum_{n=1}^{5}\left(x^{n}+\frac{1}{x^{n}}\right)^{2}\) is
- 8
- 10
- 12
- 14
Answer
(D) 14
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