If 7 and r are the roots of the equation p x^ 2 +q x+r=0 , then
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
If \(\sin 7\) and \(\cos \mathrm{r}\) are the roots of the equation \(p x^{2}+q x+r=0\), then
- \(p^{2}+q^{2}-2 p r=0\)
- \(p^{2}-q^{2}+2 p r=0\)
- \(p^{2}-q^{2}-2 p r=0\)
- \(p^{2}+q^{2}+2 q r=0\)
Answer
(C) p^ 2 -q^ 2 -2 p r=0
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