Let II and be the roots of equation p x^ 2 +q x+r=0, p 0 . If p, q, r are in A.P. and 1 x…
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
Let \(\text { II }\) and \(\beta\) be the roots of equation \(p x^{2}+q x+r=0, p \neq 0\). If p, q, r are in A.P. and \(\frac{1}{x}+\frac{1}{\beta}=4\), then the value of \(|\boldsymbol{\pi}-\boldsymbol{\beta}|\) is :
- \(\frac{\sqrt{34}}{9}\)
- \(\frac{2 \sqrt{13}}{9}\)
- \(\frac{\sqrt{61}}{9}\)
- \(\frac{2 \sqrt{17}}{9}\)
Answer
(D) 2 17 9
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